`a = 75.4, b = 52, c = 52` Use Heron's Area Formula to find the area of the triangle.

Given: `a=75.4, b=52, b=52`

Heron's area formula `A=sqrt[s(s-a)(s-b)(s-c)]`

where `s=(a+b+c)/2`

`s=(75.4+52+52)/2=179.4/2=89.7`

`A=sqrt[(89.7)(89.7-75.4)(89.7-52)(89.7-2)]`

`A=sqrt[(89.7)(14.3)(37.7)(37.7)]`

`A=1350.22`

The area is 1350.22 squared units.

Given: `a=75.4, b=52, b=52`

Heron's area formula `A=sqrt[s(s-a)(s-b)(s-c)]`

where `s=(a+b+c)/2`

`s=(75.4+52+52)/2=179.4/2=89.7`

`A=sqrt[(89.7)(89.7-75.4)(89.7-52)(89.7-2)]`

`A=sqrt[(89.7)(14.3)(37.7)(37.7)]`

`A=1350.22`

The area is 1350.22 squared units.