A truck is traveling at a constant velocity of 20m s^-1 (72 km.h^-1) when the driver sees a child 50 m in front of him, on the road. He hits the...

Speed of the truck = 20 m/s

distance to the child = 50 m

Acceleration = -1.25 m/s^2

Reaction time = 0.5 s

During the 0.5 seconds, that the driver takes to hit the brakes, the truck will travel 10 m ( = 20 m/s x 0.5 sec).

Using the equation of motion, relating initial and final velocity, acceleration and distance traveled: v^2 = u^2 + 2as

we can calculate the distance traveled by assuming...

Speed of the truck = 20 m/s

distance to the child = 50 m

Acceleration = -1.25 m/s^2

Reaction time = 0.5 s

During the 0.5 seconds, that the driver takes to hit the brakes, the truck will travel 10 m ( = 20 m/s x 0.5 sec).

Using the equation of motion, relating initial and final velocity, acceleration and distance traveled: v^2 = u^2 + 2as

we can calculate the distance traveled by assuming final velocity to be zero.

thus, s = (v^2 - u^2)/2a = -(20x20)/(2x-1.25) = 160 m.

Thus, the truck will travel a total distance of 170 m (= 10 m + 160 m) before it stops. Since the child is only 50 m in front of the truck, the truck will (unfortunately) hit the child, before it stops.

Hope this helps.