Notes: `B = 130^@, a = 62, c = 20` Find the area of the triangle having the indicated angle and sides.

Monday, 13 October 2014

Given $\displaystyle{{B}}^{\circ}={130},{a}={62},{c}={20}$

Use the Area formula $\displaystyle{A}=\frac{{1}}{{2}}{\left({a}\right)}{\left({c}\right)}{\sin{{\left({{B}}^{\circ}\right)}}}$

$\displaystyle{A}=\frac{{1}}{{2}}{\left({62}\right)}{\left({20}\right)}{\sin{{\left({130}\right)}}}$

$\displaystyle{A}={474.95}$

The area is 474.95 squared units.

Given $\displaystyle{{B}}^{\circ}={130},{a}={62},{c}={20}$

Use the Area formula $\displaystyle{A}=\frac{{1}}{{2}}{\left({a}\right)}{\left({c}\right)}{\sin{{\left({{B}}^{\circ}\right)}}}$

$\displaystyle{A}=\frac{{1}}{{2}}{\left({62}\right)}{\left({20}\right)}{\sin{{\left({130}\right)}}}$

$\displaystyle{A}={474.95}$

The area is 474.95 squared units.

Notes