`B = 75^@ 20', a = 6.2, c = 9.5` Use the Law of Cosines to solve the triangle. Round your answers to two decimal places.

Given: `B=75^@20', a=6.2, c=9.5`

`b^2=a^2+c^2-2ac*cos(B)`

`b^2=6.2^2+9.5^2-2(6.2)(9.5)cos(75^@20')`

`b^2=98.8636`

`b=9.94`

`cos(C)=(a^2+b^2-c^2)/(2ab)`

`cos(C)=[6.2^2+9.94^2-9.5^2]/(2*6.2*9.94)`

`cos(C)=.3813`

`C=arccos(.3813)`

`C=67.60^@`

`A=180-75.33-67.60`

`A=37.01^@`

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Given: `B=75^@20', a=6.2, c=9.5`

`b^2=a^2+c^2-2ac*cos(B)`

`b^2=6.2^2+9.5^2-2(6.2)(9.5)cos(75^@20')`

`b^2=98.8636`

`b=9.94`

`cos(C)=(a^2+b^2-c^2)/(2ab)`

`cos(C)=[6.2^2+9.94^2-9.5^2]/(2*6.2*9.94)`

`cos(C)=.3813`

`C=arccos(.3813)`

`C=67.60^@`

`A=180-75.33-67.60`

`A=37.01^@`

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