`4 - 4sqrt(3)i` Write the trigonometric form of the number.

`z=4-4sqrt3i`

`r=sqrt(4^2+(-4sqrt3)^2)=sqrt(16+48)=sqrt(64)=8`

`theta=arctan((-4sqrt3)/4)=arctan(-sqrt3)=(5pi)/3`

`z=8(cos((5pi)/3)+isin((5pi)/3))`

`z=4-4sqrt3i`

`r=sqrt(4^2+(-4sqrt3)^2)=sqrt(16+48)=sqrt(64)=8`

`theta=arctan((-4sqrt3)/4)=arctan(-sqrt3)=(5pi)/3`

`z=8(cos((5pi)/3)+isin((5pi)/3))`