`A = 24.3^@, C = 54.6^@, c = 2.68` Use the law of sines to solve the triangle. (Find missing sides/angles) Round answers to 2 decimal places.

Given: `A=24.3^@, C=54.6^@, c=2.68`

The Law of Sines:  `a/sin(A)=b/sin(B)=c/sin(C)`

`B=180-24.3-54.6=101.1^@`

`a/sin(24.3)=b/sin(101.1)=2.68/sin(54.6)`

`a/sin(24.3)=2.68/sin(54.6)`

`a=[2.68sin(24.3)]/sin(54.6)`

`a=1.35`

`b/sin(101.1)=2.68/sin(54.6)`

` ` `b=[2.68sin(101.1)]/sin(54.6)`

`b=3.23 `

``

Given: `A=24.3^@, C=54.6^@, c=2.68`

The Law of Sines:  `a/sin(A)=b/sin(B)=c/sin(C)`

`B=180-24.3-54.6=101.1^@`

`a/sin(24.3)=b/sin(101.1)=2.68/sin(54.6)`

`a/sin(24.3)=2.68/sin(54.6)`

`a=[2.68sin(24.3)]/sin(54.6)`

`a=1.35`

`b/sin(101.1)=2.68/sin(54.6)`

` ` `b=[2.68sin(101.1)]/sin(54.6)`

`b=3.23 `

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