`A = 110^@, a = 125, b = 200` Use the law of sines to solve (if possible) the triangle. If two solutions exist, find both. Round your answer...

Given:  `A=100^@, a=125, b=200`

The Law of Sines:  `a/sin(A)=b/sin(B)=c/sin(C)`

`125/sin(100)=200/sin(B)=c/sin(C)`

` `

`125/sin(100)=200/sin(B)`

`sin(B)=[200sin(100)]/125`

`sin(B)=1.57`

`B=arcsin(1.57)`

It is not possible to find angle B. A triangle cannot be formed from the given information.

Given:  `A=100^@, a=125, b=200`

The Law of Sines:  `a/sin(A)=b/sin(B)=c/sin(C)`

`125/sin(100)=200/sin(B)=c/sin(C)`

` `

`125/sin(100)=200/sin(B)`

`sin(B)=[200sin(100)]/125`

`sin(B)=1.57`

`B=arcsin(1.57)`

It is not possible to find angle B. A triangle cannot be formed from the given information.