Monday 20 March 2017

`C = 43^@, a = 4/9, b = 7/9` Use the Law of Cosines to solve the triangle. Round your answers to two decimal places.

Using the law of cosines, in the given case, yields:


`c^2 = a^2 + b^2 - 2ab*cos C`


`c^2 = (4/9)^2 + (7/9)^2 - 2*28/9*cos 43^o`


`c^2 = 65/81 - 56/81*73/10`


`c^2 = (1/81)*(650 - 4088)/10`


`c^2 =-343.8/81`


Since `c^2 > 0` , the provided information cannot be used to solve the triangle.

Using the law of cosines, in the given case, yields:


`c^2 = a^2 + b^2 - 2ab*cos C`


`c^2 = (4/9)^2 + (7/9)^2 - 2*28/9*cos 43^o`


`c^2 = 65/81 - 56/81*73/10`


`c^2 = (1/81)*(650 - 4088)/10`


`c^2 =-343.8/81`


Since `c^2 > 0` , the provided information cannot be used to solve the triangle.

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