`a = 75.4, b = 52, c = 52` Use the Law of Cosines to solve the triangle. Round your answers to two decimal places.

Given: `a=75.4, b=52, c=52`

``

`cos(A)={b^2+c^2-a^2]/(2bc)`

` ` `cos(A)=[52^2+52^2-75^2]/(2*52*52)`

`cos(A)=-.04012`

`A=arccos(-.04012)`

`A=92.30^@`

`cos(B)=(a^2+c^2-b^2)/(2ac)`

` `

`cos(B)=[75^2+52^2-52^2]/(2*75*52)`

`cos(B)=.7211`

`B=arccos(.7211)`

`B=43.85^@`

`C=180-92.30-43.85`

`C=43.85^@`

Given: `a=75.4, b=52, c=52`

``

`cos(A)={b^2+c^2-a^2]/(2bc)`

` ` `cos(A)=[52^2+52^2-75^2]/(2*52*52)`

`cos(A)=-.04012`

`A=arccos(-.04012)`

`A=92.30^@`

`cos(B)=(a^2+c^2-b^2)/(2ac)`

` `

`cos(B)=[75^2+52^2-52^2]/(2*75*52)`

`cos(B)=.7211`

`B=arccos(.7211)`

`B=43.85^@`

`C=180-92.30-43.85`

`C=43.85^@`