Sunday 21 December 2014

`x = y^4, y = sqrt(2 - x), y = 0` Sketch the region enclosed by the given curves and find its area.

`x=y^4,y=sqrt(2-x), y=0`


Refer the attached image. `x=y^4` is plotted in red color and `y=sqrt(2-x)` is plotted in blue color.The curves intersect at x=y=1.


`y=sqrt(2-x)rArry^2=2-x=>x=2-y^2`


Area of the region enclosed by the given curves A=`int_0^1((2-y^2)-y^4)dy`


`A=int_0^1(2-y^2-y^4)dy`


`A=[2y-y^3/3-y^5/5]_0^1`


`A=(2*1-1^3/3-1^5/5)`


`A=(2-1/3-1/5)`


`A=(30-5-3)/15`


`A=22/15`


`x=y^4,y=sqrt(2-x), y=0`


Refer the attached image. `x=y^4` is plotted in red color and `y=sqrt(2-x)` is plotted in blue color.The curves intersect at x=y=1.


`y=sqrt(2-x)rArry^2=2-x=>x=2-y^2`


Area of the region enclosed by the given curves A=`int_0^1((2-y^2)-y^4)dy`


`A=int_0^1(2-y^2-y^4)dy`


`A=[2y-y^3/3-y^5/5]_0^1`


`A=(2*1-1^3/3-1^5/5)`


`A=(2-1/3-1/5)`


`A=(30-5-3)/15`


`A=22/15`


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