`bbu = , bbv = ` Find (a) `bbu + bbv`, (b) `bbu - bbv`, and (c) `2bbu - 3bbv`.

You need to evaluate the sum of two vectors,`u+v` , hence you need to perform the addition of the same versors, such that:

`u = <0,0> => u = 0i + 0j`

`v = <2,1> => v = 2i + j`

`u + v = <0,0> + <2,1> `

`u + v = <0+2,0+1> => u + v = <2,1>`

Hence, evaluating the sum `u + v` yields `u + v = <2,1> `

You...

You need to evaluate the sum of two vectors,`u+v` , hence you need to perform the addition of the same versors, such that:

`u = <0,0> => u = 0i + 0j`

`v = <2,1> => v = 2i + j`

`u + v = <0,0> + <2,1> `

`u + v = <0+2,0+1> => u + v = <2,1>`

Hence, evaluating the sum `u + v` yields `u + v = <2,1> `

You need to evaluate the difference of two vectors,u-v, hence you need to perform the subtraction of the same versors, such that:

`u - v = <0,0> - <2,1>`

`u - v = <0-2,0-1> => u - v = <-2,-1> `

Hence, evaluating the difference `u - v` yields `u - v = <-2,-1> .`

You need to evaluate the difference of the vectors,`2u-3v` , hence you need to perform first the multiplication of each vector with the indicated scalar and then you need to perform the subtraction of the same versors, such that:

`2u - 3v = 2<0,0> - 3<2,1>`

`2u - 3v = <2*0,2*0> - <3*2,3*1>`

`2u - 3v = <2*0 - 3*2,2*0 - 3*1> => 2u - 3v = <-6,-3>`

Hence, evaluating the difference `2u - 3v` yields `2u - 3v = <-6,-3>.`