`int (dx)/(5 - 3x)` Evaluate the indefinite integral.

You need to use the following substitution 5 - 3x = t, such that:

`5 - 3x = t => -3dx = dt => dx = -(dt)/3`

`int (dx)/(5 -3x) = -(1/3) int (dt)/t`

`-(1/3) int (dt)/t = -(1/3) ln |t| + c`

Replacing back 5 - 3x for t yields:

`int (dx)/(5 -3x) = -(1/3) ln |5 - 3x| + c`

Hence, evaluating the indefinite integral, yields`int (dx)/(5 -3x) = -(1/3) ln |5...

You need to use the following substitution 5 - 3x = t, such that:

`5 - 3x = t => -3dx = dt => dx = -(dt)/3`

`int (dx)/(5 -3x) = -(1/3) int (dt)/t`

`-(1/3) int (dt)/t = -(1/3) ln |t| + c`

Replacing back 5 - 3x for t yields:

`int (dx)/(5 -3x) = -(1/3) ln |5 - 3x| + c`

Hence, evaluating the indefinite integral, yields `int (dx)/(5 -3x) = -(1/3) ln |5 - 3x| + c.`