`B = 28^@, C = 104^@, a = 3 5/8` Use the law of sines to solve the triangle. (Find missing sides/angles) Round answers to 2 decimal places.

Given:  `B=28^@, C=104^@, a=3.625`

The Law of Sines: `a/sin(A)=b/sin(B)=c/sin(C)`

`A=180-28-104=48^@`

`3.625/sin(48)=b/sin(28)=c/sin(104)`

`3.625/sin(48)=b/sin(28)`

`b=[3.625sin(28)]/sin(48)`

`b =2.29`

`3.625/sin(48)=c/sin(104)`

`c=[3.625sin(104)}/sin(48)`

`c=4.73`

Given:  `B=28^@, C=104^@, a=3.625`

The Law of Sines: `a/sin(A)=b/sin(B)=c/sin(C)`

`A=180-28-104=48^@`

`3.625/sin(48)=b/sin(28)=c/sin(104)`

`3.625/sin(48)=b/sin(28)`

`b=[3.625sin(28)]/sin(48)`

`b =2.29`

`3.625/sin(48)=c/sin(104)`

`c=[3.625sin(104)}/sin(48)`

`c=4.73`