Notes: HOW we get answer 29 from 1,2,3,4 numbers using at once

Friday, 9 January 2015

The process is by trial and error.

The following operations will produce 29 as an answer. The order of operation rules must be applied.

$\displaystyle{{\left({2}\right)}}^{{{4}+{1}}}-{3}$

$\displaystyle={{\left({2}\right)}}^{{5}}-{3}$

$\displaystyle={32}-{3}$

$\displaystyle={29}$

The following operations will also produce 29 as and answer. The order of operation rules must be applied.

$\displaystyle{{\left({1}+{2}\right)}}^{{3}}+\sqrt{{4}}$

$\displaystyle={{\left({3}\right)}}^{{3}}+\sqrt{{4}}$

$\displaystyle={27}+\sqrt{{4}}$

$\displaystyle={27}+{2}$

$\displaystyle={29}$

The process is by trial and error.

The following operations will produce 29 as an answer. The order of operation rules must be applied.

$\displaystyle{{\left({2}\right)}}^{{{4}+{1}}}-{3}$

$\displaystyle={{\left({2}\right)}}^{{5}}-{3}$

$\displaystyle={32}-{3}$

$\displaystyle={29}$

The following operations will also produce 29 as and answer. The order of operation rules must be applied.

$\displaystyle{{\left({1}+{2}\right)}}^{{3}}+\sqrt{{4}}$

$\displaystyle={{\left({3}\right)}}^{{3}}+\sqrt{{4}}$

$\displaystyle={27}+\sqrt{{4}}$

$\displaystyle={27}+{2}$

$\displaystyle={29}$

Notes