When the three sides of the triangle are known, its area can be solved using the Heron's formula.
`A =sqrt(s(s-a)(s-b)(s-c))`
where a, b and c are the length of the three sides and s is half of the triangle's perimeter.
The value of s will be:
`s= (a+b+c)/2= (12.32+8.46+15.05)/2=35.83/2=17.915`
Plugging the values of s, a, b and c to the Heron's formula yields:
`A=sqrt(17.915(17.915-12.32)(17.915-8.46)(17.915-15.05))`
`A=52.11`
Therefore, the area of the triangle is 52.11 square units.
When the three sides of the triangle are known, its area can be solved using the Heron's formula.
`A =sqrt(s(s-a)(s-b)(s-c))`
where a, b and c are the length of the three sides and s is half of the triangle's perimeter.
The value of s will be:
`s= (a+b+c)/2= (12.32+8.46+15.05)/2=35.83/2=17.915`
Plugging the values of s, a, b and c to the Heron's formula yields:
`A=sqrt(17.915(17.915-12.32)(17.915-8.46)(17.915-15.05))`
`A=52.11`
Therefore, the area of the triangle is 52.11 square units.
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