Thursday 3 March 2016

What is the equation for the reaction between methylamine and sulfuric acid?

Methylamine is a weak base and can neutralize strong acids, such as hydrochloric acid, sulfuric acid, etc. The reaction between methylamine and sulfuric acid can be written as follows:


`2CH_3NH_2 + H_2SO_4 -> (CH_3NH_3)_2SO_4`


In this neutralization reaction, 2 moles of methylamine (weak base) react with 1 mole of sulfuric acid (strong acid) and generate 1 mole of a methyl ammonium salt (a salt of a weak base and a strong acid). 


In a similar...

Methylamine is a weak base and can neutralize strong acids, such as hydrochloric acid, sulfuric acid, etc. The reaction between methylamine and sulfuric acid can be written as follows:


`2CH_3NH_2 + H_2SO_4 -> (CH_3NH_3)_2SO_4`


In this neutralization reaction, 2 moles of methylamine (weak base) react with 1 mole of sulfuric acid (strong acid) and generate 1 mole of a methyl ammonium salt (a salt of a weak base and a strong acid). 


In a similar reaction, methylamine can neutralize hydrochloric acid, another strong acid. The reaction can be written as:


`CH_3NH_2 + HCl -> CH_3NH_3Cl`


Here, methylamine and hydrochloric acid react with each other and produce a salt, known as N-methyl ammonium chloride. 


It is interesting to note that the salts produced in these reactions, when dissolved in water, generate acidic ions (such as `CH_3NH_2^+` , etc.). 


Hope this helps. 

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